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Vikki [24]
2 years ago
6

Find the slope of the line that passes through (8,9) and (1, 3).

Mathematics
2 answers:
vlabodo [156]2 years ago
4 0
Rise (y) over run (x)
9-3/8-1
6/7
slope is 6/7
Finger [1]2 years ago
3 0

Answer:

m=6/7

Step-by-step explanation:

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If the measure of cae is 95° what is the measure of cba
xxTIMURxx [149]
<span>CAE=95 GAE=90 CAG=95-90=5 ACG=5 CGA=180-(5+5)=170 CBA=12—170=85</span>
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3 years ago
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Solve the equation 2x^2 + 4x - 39 to the nearest tenth.
Virty [35]

Answer:

cant be solved, when you try to you get

-1+78 = 77

which is

77 = 77

1=1

So cannot be factored

Step-by-step explanation:

8 0
2 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
Mrs Perry shares out 15 biscuits between Gemma and Zak in the ratio 1:2
Bad White [126]
<span>1x + 2x = 15 3x = 15 3x/3 = 15/3 x = 5 Gemma = 1x, Zak = 2x therefore Gemma = 5 and Zak = 10</span>
5 0
3 years ago
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Graph the line.<br> y=3x
expeople1 [14]

Answer:

desmos(dot)com/calculator/gv8jsoui4w

Step-by-step explanation:

Create a table of appropriate x values e.g. x = 2 and substitute into y=3x which will be y=3*2 meaning y=6 at the point x=2. Repeat with different x values until you have enough points to draw a straight line.

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3 years ago
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