X(1/2) = 12
x(1/2)(2) = 12(2)
x(1) = 24
x = 24
hope this helps
Answer:the answer for 15/3 = 5/1 which then equals to 5.
Step-by-step explanation:
Use the double angle identity:
sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)
Now rewrite
sin(2<em>x</em>) sin(<em>x</em>) + cos(<em>x</em>) = 0
as
2 sin²(<em>x</em>) cos(<em>x</em>) + cos(<em>x</em>) = 0
Factor out cos(<em>x</em>) :
cos(<em>x</em>) (2 sin²(<em>x</em>) + 1) = 0
Consider the two cases,
cos(<em>x</em>) = 0 OR 2 sin²(<em>x</em>) + 1 = 0
Solve for cos(<em>x</em>) and sin²(<em>x</em>) :
cos(<em>x</em>) = 0 OR sin²(<em>x</em>) = -1/2
Squaring a real number always gives a non-negative number, so the second case doesn't offer any real solutions. We're left with
cos(<em>x</em>) = 0
Cosine is zero for odd multiples of <em>π</em>/2, so we have
<em>x</em> = (2<em>n</em> + 1) <em>π</em>/2
where <em>n</em> is any integer.
Answer:
Angle of elevation: 68.2°, distance from Mr. clanton to the eagle: 32.3m.
Step-by-step explanation:
I can't draw the diagram , but will try to explain:
the diagram is a right angled triangle, with the opposite as the rig, the adjacent as the distance between mr. clinton and the base of the rig, and the hypotenuse as x.
∅ is the angle of elevation from clinton to the eagle.
Using SOH CAH TOA,
Tan∅ =30÷12
tan∅ =2.5.
∅ =tan^-1( tan raised to power -1 )
∅ =tan^-1(2.5)
∅ = 68.19859051≅68.2 to 3s.f.
To get the distance between mr. clinton and the eagle:
Using SOH CAH TOA;
Cos68.2 =12/x cross multiplying....
x*cos68.2 =12
∴ x = 12 ÷ cos 68.2
= 12 ÷ 0.3713678356
= 32.31297611≅32.3 to 3s.f.
Hope this helps.....
Answer:
18x + 91
Step-by-step explanation: