Answer:
a) The mean is 
b) The standard deviation is 
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.
This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when 
So




The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.
This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when 
So




Since we also have that 





Question
The mean is 
The standard deviation is 
Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:

Compute the degrees of freedom as follows:


Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:


*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer:
its all sides are equal and diagonal make 90° angle.
so, the answer option c.
Answer:
if u take 1 degree to 78 its answer is 79
Step-by-step explanation:
got it?
Answer:
0.815
Step-by-step explanation:
First, find the z-scores.
z = (x − μ) / σ
z₁ = (8 − 10) / 1
z₁ = -2
z₂ = (11 − 10) / 1
z₂ = 1
P(-2 < Z < 1) = P(Z < 1) − P(Z < -2)
Use a chart, calculator, or the empirical rule to find the probability.
Using the empirical rule:
P(-2 < Z < 1) = 0.84 − 0.025
P(-2 < Z < 1) = 0.815
Using a chart:
P(-2 < Z < 1) = 0.8413 − 0.0228
P(-2 < Z < 1) = 0.8185