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olganol [36]
3 years ago
11

What is 1.939 x 10^5 in standard form?​

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

193900

Step-by-step explanation:

thx for points

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Write an equation of the line in point-slope form that passes through the given points (-3,2) (5,5)
daser333 [38]
I think it is: y=0.375x+3.125

a=(5-2)/(5- -3)=3/8=0.375

Find b

(5)=0.375(5)+b
(5)=1.875+b
5-1.875=b
b=3.125
3 0
2 years ago
Help Please..
8_murik_8 [283]
4a^2-6a+8
3 0
3 years ago
In the figure below ABCD is a rectangle and DA and CB are radii of circles tangent externally, AB = 4 cm. Provide the answer in
ad-work [718]

Answer:

a. Radius of DA - 2 cm.

b. Area of rectangle ABCD -

c. Area of shaded - 8-4π

d. Perimeter of shaded region - also 8-4π

<em><u>Hope this helps!  </u></em>

3 0
3 years ago
A map scale shows a scale of 1 inch = 50 miles. How many miles are represented by 4.5 inches on the map?
a_sh-v [17]

Answer:

Step-by-step explanation:

take 50*4.5 and you'll get your answer

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%
Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

The domain refers to all values of x for which the function is defined.

The function is defined for

x^4+x^3-4x^2-4\ne0

This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0
3 years ago
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