Answer:
0.75
Step-by-step explanation:
Answer:
The other endpoint of the segment is 
.
Step-by-step explanation:
The midpoint of the points 
and 
is given by the following formula:
where 
= coordinates of the midpoint.
We know that the midpoint is (-15, 2) and an endpoint is (-12, 11). Substituting the information we have gives:
To find 
we need to solve this equation:
and to find 
we need to solve this equation:
The other endpoint of the segment is 
.
Answer:
Product – Attributes of an organization or offering within this segment include delivery system design, technology, quality, services provided and their availability.
Price – This silo of the marketing mix includes costs to users/supporters, payment periods, arrangements and terms. Note: Some have also argued “costs” are more than dollars … a full cost analysis should include emotional (for those seeking greater purpose, advancements, victory), sacrificial (for people giving time, energy, focus) and relational (what does one’s association with an organization do for their relationships … will people think more or less of them).
Place – An often-overlooked part of the marketing mix, this “P” covers strategy and executional elements surrounding service distribution channels, coverage, locations, logistics and e-services.
Promotion – Likely the most known aspect of the marketing mix, this piece considers strategies and tactics related to advertising, logo/identity and promotions. But it also covers development/fundraising, communications, events and public relations as they are all tools to be considered and deployed as part of the greater marketing and branding strategy.
By algebra properties we find the following relationships between each pair of algebraic expressions:
- First equation: Case 4
- Second equation: Case 1
- Third equation: Case 2
- Fourth equation: Case 5
- Fifth equation: Case 3
<h3>How to determine pairs of equivalent equations</h3>
In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:
First equation
(7 - 2 · x) + (3 · x - 11)
(7 - 11) + (- 2 · x + 3 · x)
- 4 + (- 2 + 3) · x
- 4 + (1) · x
- 4 + (5 - 4) · x
- 4 - 4 · x + 5 · x
- 4 · (x + 1) + 5 · x → Case 4
Second equation
- 7 + 6 · x - 4 · x + 3
(6 · x - 4 · x) + (- 7 + 3)
(6 - 4) · x - 4
2 · x - 4
2 · (x - 2) → Case 1
Third equation
9 · x - 2 · (3 · x - 3)
9 · x - 6 · x + 6
3 · x + 6
(2 + 1) · x + (14 - 8)
[1 - (- 2)] · x + (14 - 8)
(x + 14) - (8 - 2 · x) → Case 2
Fourth equation
- 3 · x + 6 + 4 · x
x + 6
(5 - 4) · x + (7 - 1)
(7 + 5 · x) + (- 4 · x - 1) → Case 5
Fifth equation
- 2 · x + 9 + 5 · x + 6
3 · x + 15
3 · (x + 5) → Case 3
To learn more on algebraic equations: brainly.com/question/24875240
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