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AlladinOne [14]
3 years ago
15

Bob wants to put down new sod in his backyard except for the part set aside for his flower garden the diagram shows bobs backyar

d and the flower garden

Mathematics
1 answer:
zmey [24]3 years ago
0 0

Answer:

Bob will need 235\ yd^{2} of sod

Step-by-step explanation:

step 1

Find the area of the backyard

A=20(14)=280\ yd^{2}

step 2

Find the area of the flower garden

A=5(9)=45\ yd^{2}

step 3

Find the difference

280\ yd^{2}-45\ yd^{2}=235\ yd^{2}

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Here is a rectangle which has a width of x cm. x cm
miskamm [114]

Answer:

278.25 cm2

Step-by-step explanation:

If the width of the rectangle is x (cm), as the length is 8cm longer, so that the length of the rectangle is: x + 8 (cm).

In the attached image, we can see the length of each side. Total length of the sides are 90 cm.

=> (x + x + 8) + x + 8 + (x+8) + (x + x + 8) + x + 8 + (x +8) = 90

=> 8x + 48 = 90

=> 8x = 90 - 48 = 42

=> x =42/8 = 5.25 (cm)

=> The width of the rectangle is 5.25cm

=> The length of the rectangle is: 5.25 + 8 = 13.25 cm

=> The area of one rectangle is: Length x Width = 5.25 x 13.25 = 69.5625 cm2

As the 8-sided shape is made from 4 rectangles, so that:

Area of 8 sided shape = 4 x Area of the rectangle = 4 x 69.5625 = 278.25 cm2

6 0
3 years ago
Can someone please help me on this question
Grace [21]

Answer: ? = 72

Step-by-step explanation:

   We will set up a proportion to solve.

\displaystyle \frac{?}{56} =\frac{45}{35}

   Now, we will cross-multiply.

? * 35 = 56 * 45

35? = 2,520

? = 72

3 0
2 years ago
Sarah is trying to convince her friend Brianna that the exponential function f(x) = 2x will eventually grow larger than the poly
atroni [7]
C) 1000.

2^1000 = 1^301, whereas 1000^30 is 1^90
5 0
3 years ago
Read 2 more answers
If two angles are supplementary and one angle is 84°, what is the measure of the other angle?
vekshin1
96 degrees is your answer

supplementary means the angles add up to be 180 degrees. if 1 angle is 84 degrees then 180-84=96
7 0
3 years ago
Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec
o-na [289]

Answer:

(a) The probability of the event (<em>X</em> > 84) is 0.007.

(b) The probability of the event (<em>X</em> < 64) is 0.483.

Step-by-step explanation:

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 64.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...

(a)

Compute the probability of the event (<em>X</em> > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

                =1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007

Thus, the probability of the event (<em>X</em> > 84) is 0.007.

(b)

Compute the probability of the event (<em>X</em> < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

                =\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483

Thus, the probability of the event (<em>X</em> < 64) is 0.483.

5 0
3 years ago
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