Why you ain't search it up on line
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
![12^{2x-1}=(\sqrt[4]{12})^{x}\\\\ 12^{2x-1}= (12^{\frac{1}{4}})^{x}\\\\12^{2x-1}=12^{\frac{1}{4}*x}\\](https://tex.z-dn.net/?f=12%5E%7B2x-1%7D%3D%28%5Csqrt%5B4%5D%7B12%7D%29%5E%7Bx%7D%5C%5C%5C%5C%2012%5E%7B2x-1%7D%3D%20%2812%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%29%5E%7Bx%7D%5C%5C%5C%5C12%5E%7B2x-1%7D%3D12%5E%7B%5Cfrac%7B1%7D%7B4%7D%2Ax%7D%5C%5C)
Bases are same. So, compare the exponents.

Multiply the entire equation by 4
4*(2x - 1) = x
8x - 4 = x
8x = x + 4
8x -x = 4
7x = 4
x = 4/7
Answer:
0.2(2 tenths) times 0.3(3 tenths) = 0.06
Step-by-step explanation:
2 times 3 equals 6.
The 6 would have a 0 before it because you are using multiplication. If you were using addition, it would be 0.5(5 tenths) since you are adding tenths.