The answer is; extremophiles
These organisms are found in places on earth that would be damaging to most life on earth. There are different categories of extremophiles depending on their environment. For example, those that live in the extreme cold (even below 150C ) are called Psychrophiles while Xerophiles live extreme desiccation.
Answer and Explanation:
The molar mass of a substance is all of the weights from the elements combined.
So, we have the elements
CU, S, and 
CU has a mass is 65
S mass is 32
O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.
Now we add.
65 + 32 + 64 is 161.
<u>So, the answer is 160, or answer choice A.</u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
<h3>
Answer:</h3>
19.3 g/cm³
<h3>
Explanation:</h3>
Density of a substance refers to the mass of the substance per unit volume.
Therefore, Density = Mass ÷ Volume
In this case, we are given;
Mass of the gold bar = 193.0 g
Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm
We are required to get the density of the gold bar
Step 1: Volume of the gold bar
Volume is given by, Length × width × height
Volume = 0.50 cm × 10.0 cm × 2.0 cm
= 10 cm³
Step 2: Density of the gold bar
Density = Mass ÷ volume
Density of the gold bar = 193.0 g ÷ 10 cm³
= 19.3 g/cm³
Thus, the density of the gold bar is 19.3 g/cm³
B since Oxygen is more electronegative, meaning they have a strong stronger pull on the electrons creating poles
Answer:
869 g Cl₂O
Explanation:
To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).
1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)
Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol
Molar Mass (Cl₂O): 86.904 g/mol
10.0 moles SO₂ 1 mole Cl₂O 86.904 g
------------------------ x ---------------------- x ------------------ = 869 g Cl₂O
1 mole SO₂ 1 mole
