Answer:
Its B Nylon
Explanation:
i just took the quiz and got it right.
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 =
![\frac{[H^+][HC2O4^-]}{[H2C2O4]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH%5E%2B%5D%5BHC2O4%5E-%5D%7D%7B%5BH2C2O4%5D%7D%20)
= x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
Answer is: reaction is second order with respect to a.
This second order reaction<span> is proportional to the square of the concentration of reactant a.
</span>rate of reaction = k[a]².
k is second order rate constant and have unit M⁻¹·s⁻¹.
Integrated rate law for this reaction: <span><span>1/[a]</span>=<span>1/<span>[a]</span></span></span>₀ <span>+ kt.
t is time in seconds..</span>
<u>Answer:</u>
The common name for the compound H2O is water.
<u>Explanation:</u>
The systemic name of H2O is Dihydrogen monoxide.
Answer:
True.
Hope this helps!
let me know if u get it right