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Sever21 [200]
3 years ago
6

What are the products in the equation for cellular respiration? A. Oxygen and lactic acid b. Carbon dioxide and water c. Glucose

and oxygen d. Water and glucose
Chemistry
1 answer:
Colt1911 [192]3 years ago
4 0
<span>Cellular respiration is the chemical reaction in which glucose and oxygen are turned into water, carbon dioxide, and energy. Now you know the answer. :P</span>
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The reduction of nitrogen monoxide is described by the following chemical equation: 2H2 (g) +2NO (g) 2H20 ()N2 (g Suppose a two-
Ipatiy [6.2K]

Answer:

Reasonable Second step- N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

Explanation:

The given single step chemical reaction is as follows.

2H_{2}(g)+2NO \rightarrow 2H_{2}O(g)+N_{2}(g)

Suppose a two-step mechanism is proposed for this reaction,

The reaction occured in two steps they are as follows.

Step -1:H_{2}(g)+2NO \rightarrow N_{2}O(g)+H_{2}O(g)

Step-2:N_{2}O(g)+H_{2}(g)\rightarrow N_{2}(g)+H_{2}O(g)

8 0
3 years ago
What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH)<br> 3?
S_A_V [24]

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>

<em />

<em>Molar mass Fe(OH)3 and oxygen:</em>

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
7 0
3 years ago
Can someone please helpppp!
dolphi86 [110]

Answer: A

Aloha is the one that loses a helium

5 0
3 years ago
How do exothermic and endothermic differ
Ber [7]

Answer:

Explanation:

exothermic reactions involve release of heat whereas endothermic reaction involve absorption of heat.

6 0
2 years ago
Read 2 more answers
Write the formulas for the following compounds: (a) rubidium nitrite, (b) potassium sulfide, (c) sodium hydrogen sulfide, (d) ma
choli [55]

Answer:

All are having different valent cation and anion like mono,di and trivalent polyatomic ions .

A. RbNO3

B. K2S

C. NaHS

D. Mg3(PO4)2 formed by divalent Mg+2 and trivalent PO43-

E. CaHPO4

F. PbCO3 , lead is in Pb+2 form

G. SnF2

H. (NH4)2SO4

I. AgClO4

J. BCl3

6 0
3 years ago
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