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Helga [31]
3 years ago
11

A hyperbola centered at the origin has vertices at (0,±\sqrt(54) and foci at (0,±\sqrt(89)

Mathematics
1 answer:
mestny [16]3 years ago
3 0

answer:The equation has the form y2a2−x2b2=1 y 2 a 2 − x 2 b 2 = 1 , so the transverse axis lies on the y-axis. The hyperbola is centered at the origin, so the vertices serve as the y-intercepts of the graph. To find the vertices, set x=0 x = 0 , and solve for y y .

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Answer:

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Step-by-step explanation:

To find the P (A^B), we add the probability of events A and B.

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LCD is 15.

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Answer:

<u></u>

  • <u>See below</u>

Explanation:

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In <em>interval notation</em> it is:

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In form of <em>inequaliy</em> that is:

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Answer:

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Step-by-step explanation:

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