Let x = your number.
6x = x^2 - 27. Subtract 6x from each side.
0 = x^2 - 6x - 27. Factor
0 = (x-9) (x+3). Set each term equal to zero
(x+3) = 0. Subtract 3 from each side.
x = -3. This is the negative solution.
(x-9) = 0. Add 9 to each side.
x = 9. This is the positive solution.
Each time they assume the sum<span> is </span>rational<span>; however, upon rearranging the terms of their equation, they get a contradiction (that an </span>irrational number<span> is equal to a </span>rational number<span>). Since the assumption that the </span>sum of a rational<span> and </span>irrational number<span> is </span>rational<span>leads to a contradiction, the </span>sum<span> must be </span>irrational<span>.</span>
- 6/2c is the correct solution
collect like terms : 3cx - cx = 2cx
hence 2cx = - 6
dividing both sides by 2c gives x = - 6/2c
Answer:
<h2>
<em>1</em><em>1</em><em>y</em><em>+</em><em>1</em><em>6</em></h2>
<em>Solution</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
