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sattari [20]
4 years ago
13

A flashlight bulb is connected to a dry cell of voltage 2.25 V. It draws 35.0 mA (1000 mA = 1 A). What is its resistance?

Physics
1 answer:
andrew11 [14]4 years ago
7 0

Explanation:

V = IR

2.25 V = (35.0 mA × 1 A / 1000 mA) R

2.25 V = (0.0350 A) R

R = 64.3 Ω

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inna [77]

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