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3 years ago

Kindly assist on how to go about the question

Physics

1 answer:

Paul [167]3 years ago

5 0

Answer:

You need to really stop and play fortnite with me Socials 90s

Explanation:

Cuz im really good and i know i am fym

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A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand

Leokris [45]

Answer:

The squeeze will not regain its shape

Explanation:

The squeeze bottle will not regain its shape.

This is because the atmospheric pressure compresses the squeeze bottle. Since the pressure in the squeeze bottle is now not equal to the atmospheric pressure since it has been corked tightly, its internal pressure cannot balance out the atmospheric pressure and thus cancel its effect.

So, the squeeze bottle does not regain its shape due to this imbalance of pressure.

5 0

3 years ago

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake

Elanso [62]

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒ $V=f\times \lambda$

or,

⇒ $f=\frac{V}{\lambda}$

On substituting the values, we get

⇒ $=\frac{2}{1.5}$

⇒ $=1.33 \ Hz$

hence,

⇒ $\lambda_1=\frac{V_1}{f}$

On substituting the values, we get

⇒ $=\frac{1.6}{1.33}$

⇒ $=1.2 \ m$

7 0

3 years ago

I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

$a_y$ = Acceleration in y axis = $9.81\ \text{m/s}^2$

$u_y$ = Initial velocity in y axis = 0

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$