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marusya05 [52]
3 years ago
10

a circuit element having terminals a and b has vab = 10v and iba = 2a over a period of 20s, how much charge moves throught the e

lement
Physics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer: charge Q = 40Coulombs

Explanation: The current in a circuit is the quantity of charge that flows through it per second.

Here the 2amp current is same as the amount of charge in coulomb that flows through the terminal in ONE second.

So, if 2 coulomb of charge flows in 1sec then in 20 secs we will have

Q(charge) = 2*20 = 40 coulombs

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.The path of a celestial body or an artificial satellite as it revolves around another body due to their mutual gravitational <span>attraction.</span>
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4 years ago
Which situation would most likely increase the carrying capacity for humans in a certain region
marta [7]

Of the following given choices;

A. A higher fertility rate

B. Less access to medicine

C. A new source of fresh water

D. A higher birthrate

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8 0
3 years ago
Read 2 more answers
A cylindrical Nickel rod (9 mm diameter, 50 m long) is pulled in tension with a load of 6,283 N. What would the elongation of th
Norma-Jean [14]

Answer:

0.29 m

Explanation:

9 mm = 0.009 m in diameter

Cross-sectional area A = \pi d^2/4 = \pi * 0.009^2/4 = 6.36\times 10^{-5} m^2

Let the tensile modulus of Nickel E = 170 \times 10^9Pa.

The elongation of the rod can be calculated using the following formula:

\Delta L = \frac{F L}{A E} = \frac{6283*50}{6.36\times 10^{-5} * 170 \times 10^9} = \frac{314150}{1081200} = 0.29 m

6 0
4 years ago
A bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.
Elan Coil [88]

Answer:

2592 km/h

Explanation:

Given that a bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.

The velocity = 720 m/s

Solution

To convert metres per second to kilometer per hour, you will multiply by 3600 and divide by 1000

720 × 3600/1000

720 × 3.6

72 × 36

2592 km/h

Therefore, the velocity of the bullet in kilometer per hour is 2592 km/h

8 0
3 years ago
In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, where the radius of the orbit is
Alchen [17]

Answer:

(a) Electric force will be 77.285\times 10^{-9}N

(B) Velocity v=2.1522\times 10^6m/sec

Explanation:

We have given that radius of the circular orbit r=0.546\times 10^{-10}m

Charge on electron e=1.6\times 10^{-19}C

(A) According to coulomb's law electric force between two charges is given by

F=\frac{kq}{r^2}

So electric force F=\frac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.546\times 10^{-10})^2}=77.285\times 10^{-9}N

We know that centripetal force is given by F=\frac{mv^2}{r}

So \frac{9.11\times 10^{-31}\times v^2}{0.546\times 10^{-10}}=77.285\times 10^{-9}

v=2.1522\times 10^6m/sec

8 0
3 years ago
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