Force equals mass*acceleration
F = ma
Given m = 54.87 kg, a = 9.8 m/s^2
F = (54.87)(9.8)
F = 537.726
F = 538 N
A force of al least 538 Newtons is required to move the object.
The kinetic energy is greater on the second hill
hope i helped have a great day
h =(3.7 - .58)m = 3.12m
Now put PE into KE and we have to use the formula:
√2gh (g = gravity and h = height) therefor:
√2 x 9.8 x 3.12
= 7.82m/s
I hope this helps!
Class 1 lever
Explanation:
In a class 1 lever, the fulcrum is placed between the effort and the load. This lever systems is the most common.
- The effort is the force input and the load is the force output
- The fulcrum is a hinge between the load and effort.
- Movement of the effort and load are in opposite directions.
- There are other classes of lever like the class 2 and 3.
- They all have different load, fulcrum and effort configurations
learn more:
Load related problems brainly.com/question/9202964
Torque brainly.com/question/5352966
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