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3 years ago

Can someone please solve these questions

Mathematics

1 answer:

k0ka [10]3 years ago

6 0

1)

=> m∠2 = 2x +13
=> m∠1 = 4x - 1
Since YP angle bisector the angles with be equal to each other,

m∠1 = m∠2
2x + 13 = 4x - 1
2x - 4x = -1 -13
-2x = -14
x = 7

All other questions are to be done in that way, don't be lazy :P

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HELP PLEASE, I will mark brainless

ahrayia [7]

To find the slope take two ordered pairs and put them in form of x2-x1/y2-y1 and then you can find the slope.

(-2,17) (-3,20)

(-2)-(-3) = 1
(17)-(20)=-3

slope is 1/-3

4 0

2 years ago

Which of the following is a quadratic equation that has the roots x = 2 and x = −7? (4 points)

crimeas [40]

Answer:

x^2 + 5x - 14

Step-by-step explanation:

We can assume that if there is 2 options for x, this is a quadratic equation that equals 0.

Therefore, we can put this into brackets as one bracket must equal 0.

(x - 2) (x + 7)

After this we expand, which is a process easier to search up

The answer is:

x^2 + 7x - 2x - 14

We can simplify this to:

x^2 + 5x - 14

x^2 represents x squared in case you were wondering

Therefore, the answer is:

x^2 + 5x - 14

8 0

2 years ago

Lines a and b in the figure above are parallel. What is the value of p?

elena-s [515]

It will be c- 20:
4q and 2(q+30) have to equal the same therefore q=30 which makes both these equations equal.
3p + 4q then have to equal 180 as they are on a straight line so you know q=30 so 4x30=120 so 180-120=60
Then 60/3=20 and that is your answer.
Hope this helps :)

7 0

3 years ago

Read 2 more answers

I need help 6x-2y=10 x-2y=-5 solve by elimination

dem82 [27]

<h3>Explanation</h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$

Hence, the value of y is 4. Therefore, we can say that when x = 3, y = 4.

Answer Check by substituting both x and y values in both equations.

First Equation

$6x - 2y = 10 \\ 6(3) - 2(4) = 10 \\ 18 - 8 = 10 \\ 10 = 10 \longrightarrow \sf{true} \: \green{ \checkmark}$

Second Equation

$x - 2y = - 5 \\ 3 - 2(4) = - 5 \\ 3 - 8 = - 5 \\ - 5 = - 5 \longrightarrow \sf{true} \: \green{ \checkmark}$

Hence, both equations are true for x = 3 and y = 4. Therefore, the solution is (3,4)

<h3>Answer</h3>

$\begin{cases} x = 3 \\ y = 4 \end{cases} \\ \sf \underline{Coordinate \: \: Form} \\ (3,4)$

8 0

3 years ago

CS Algebra

CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0

2 years ago