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faust18 [17]
2 years ago
7

What is the length of side XY as shown on the coordinate plane?

Mathematics
1 answer:
mamaluj [8]2 years ago
7 0

Answer:

4 units

Step-by-step explanation:

i took the test :) gl

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By using the table in the handbook, the present value of $12,000 for six years compounded at 6 percent semiannually is
denis23 [38]
Take a look at the attachment to see the solution.
A = future value
P = principal (P = 12,000)
r = interest rate (r=6)
n = time periods (n=12)

6 0
3 years ago
really need help on these two questions for geometry, please actually answer it instead of just grabbing points and leaving :'),
egoroff_w [7]

Answer:

Step-by-step explanation:

The diagonals of a rhombus are perpendicular, so ∠AED = 90° and ∠BEC = 90°.

∠DAE = 180° - ∠AED - ∠EDA = 180° - 90° - 35° = 55°

BD is a transversal across parallel sides AD and BC, so ∠EBC = ∠EDA = 35°.

∠BCE = 180° - ∠BEC - ∠EBC = 180° - 90° - 35° = 55°

5 0
2 years ago
Alexis has a pocket full of coins that consists of dimes and nickels. She has a total of 40 coins. The total value of her coins
MrMuchimi

Answer

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Step-by-step explanation:


4 0
3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
Pls help 20 points and mark brainliest
tatiyna
1:equilateral
2:isosceles
3:scalene
4:right
5:acute
6:obtuse
8 0
2 years ago
Read 2 more answers
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