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deff fn [24]
3 years ago
9

A border collie is on sale at a 20% discount. If it normally sells for $475.00, what is the sale price?

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0
What you have to do is multiply 475.00 by .20. Then from there yousubtract 475-(475*.20). From there you will get the answer.
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Pls help (this is for a frend)
son4ous [18]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$5\\ P=\textit{original amount deposited}\\ r=rate\to 1.25\%\to \frac{1.25}{100}\dotfill &0.0125\\ t=years\dotfill &\frac{1}{2} \end{cases} \\\\\\ 5 = (P)(0.0125)(\frac{1}{2})\implies \cfrac{5}{(0.0125)(\frac{1}{2})}=P\implies 800=P

4 0
2 years ago
Help me please with this I will give brainliest
MAVERICK [17]

Answer:

1. 18

2. 72

3. 90%

Step-by-step explanation:

For number 1

To find percentage you multiply the total number of kids with the percentage.

To do this you have to convert the percent into a decimal by moving the dot 2 times from its original location Ex. 20% = .20 as 20 would look like 20.00 in decimal form.

So .20 x 90 = 18

For number 2

Subtract 18 and 90 to find the remanding kids

For number 3

Divide 72 and 90. Make sure the lower number is being divided.

The answer you will get is .8 so move the decimal back two times because you are converting it to a percentage."

You will then get 80.00 as an answer then from there turn it to a percentage

80%

Hope this helps!

8 0
3 years ago
Frank brought some milk home from the dairy farm. He was able to pour 12 glasses of milk. Each glass held 1/2 pint of milk.
olga2289 [7]
He brought home 6 pints of milk home
hope it helps

5 0
3 years ago
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
artcher [175]

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

5 0
2 years ago
4y (4y - 4) - 4 (-4 + 5 + 4y²)<br><br> please simplify &lt;3
sasho [114]

Answer:

16y - 4

Step-by-step explanation:

4y(4y - 4) - 4(- 4 + 5 + 4y^2)

16y - 16y - 4(1 + 4y^2)

16y - 16y - 4(4y^2 + 1)

16y^2 - 16y^2 + 4

16y - 4

5 0
3 years ago
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