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Serggg [28]
3 years ago
7

Ind the equation of the tangent line to 9x^2+16y^2=52 through (2, -1)

Mathematics
1 answer:
EastWind [94]3 years ago
6 0
Here are the steps.

In order to get the answer, first we need to get the x and y value of the center of the circle by using the equation of a circle (x^2 + y^2 = r^2)

<span>The center is (-9, -4)</span>

Once you get the center point, find the equation of the line (in a form of a radius) from the center point to point (2, -1). Get the slope.

The slope from center to point (2, -1) is 11/3

Finally, get the negative reciprocal of the slope from the previous step and form the equation using slope-intercept form ( y=mx + b). Then, that's the equation of the tangent line.

The slope of the tangent line is -3/11
The equation is y = -3/11x - 5/11

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Divide 22 hours 24 minutes 40 seconds by 7​
miskamm [114]

Answer:

3 hours 12 minutes and 5.71 seconds

Step-by-step explanation:

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4 years ago
What is the area of the rhombus shown below? AC=17 BD=15 AB=11.2 Answers: A. 255 square units B. 190.4 square units C. 16 square
Lena [83]

Answer:

D. 127.5 square units

Step-by-step explanation:

AC=17

BD=15

AB=11.5

Diagonal (1&2) are given, base of the rhombus is also given.

Height is not given

Area of a rhombus given the diagonals

=1/2×d1×d2

Where,

d1=AC=17

d2=BD=15

Area of a rhombus=1/2×d1×d2

=1/2×17*15

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D. 127.5 square units

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3 years ago
Directions: type the correct answer in each box. Use the numerals instead of words.
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0.35 X 100 = 35%

6 0
3 years ago
A group of 16 people is choosing a chairperson and vice-chairperson. They put all 16 people's names into a hat. The first name d
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2 in 16

Step-by-step explanation:

6 0
3 years ago
A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle t
ahrayia [7]

Answer:

10.67 m

Step-by-step explanation:

Velocity is given as;

v(t) = t² − t − 6

To get the distance, we will integrate the velocity equation.

x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t

Thus, from t=0 seconds to t=4 seconds., we have;

(t³/3) - (t²/2) - 6t between 0 and 4.

Thus;

Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]

Total distance = (64/3) - 8 - 24 = -10.67 m

Distance can't be negative and so we take the absolute value which is 10.67 m

7 0
3 years ago
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