The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
The given parameters;
<em>Mass of the first object, m1 = 1 kg</em>
<em>Mass of the second object, m2 = 5 kg</em>
The final velocity of the objects during the downward motion is calculated as follows;
The time of motion of the object from the given height is calculated as;
The time of motion of each object is independent of mass of the object.
Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
Learn more about time of motion here: brainly.com/question/2364404
- The mechanic did 5406 Joules of work pushing the car.
That's the energy he put into the car. When he stops pushing, all the energy he put into the car is now the car's kinetic energy.
- Kinetic energy = (1/2) (mass) (speed²)
And there we have it
- The car's mass is 3,600 kg.
- Its speed is 'v' m/s .
- (1/2) (mass) (v²) = 5,406 Joules
(1/2) (3600 kg) (v²) = 5406 joules
1800 kg (v²) = 5406 joules
v² = (5406 joules) / (1800 kg)
v² = (5406/1800) (joules/kg)
= = = = = This section is just to work out the units of the answer:
- v² = (5406/1800) (Newton-meter/kg)
- v² = (5406/1800) (kg-m²/s² / kg)
= = = = =
v = √(5406/1800) m/s
<em>v = 1.733 m/s</em>
Answer:
molecules of elements
Explanation:
An element is formed of one type of atoms. An element is a pure substance. A compound is formed of atoms of different elements chemically combined together in fixed ratio. A molecule of compound has different type of atoms chemically combined. For example, a water molecule is of compound having 2 hydrogen atoms and 1 oxygen atom. A molecule of element has same type of atoms chemically combined. For example oxygen O₂ is a molecule of element.
In the given diagram, same atoms are chemically combined. Thus, these represent molecules of elements.
Answer:
a) 3.78 m/s
b) 3.78 m/s
Explanation:
a )From the equations of kinematics we know that
Vf - Vi = at
since Initial speed Vi = 0
acceleration = 4.2 m/s2
so we have
Vf = a t
= (4.2) (0.9)
= 3.78 m/s
velocity at t = 0.9 s. m/s is 3.78 m/s
b) If the sprinter maintains constant velocity then acceleration becomes zero.
So velocity is 3.78 m/s
For the gravitational force F, the Work is given by W = F*h, where h represents the height of the student.
Power P = W / t, where t is time.
