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Gnesinka [82]
2 years ago
11

What types of galaxies are these?

Physics
2 answers:
telo118 [61]2 years ago
5 0

Answer:

1. Spiral

2. Not sure but i think its irregular.

3. Elliptical

Please Vote Me Brainliest. Thank You.

Orlov [11]2 years ago
3 0

Answer:

the first one looks like a spiral galixy

the 2nd one looks like a lenticular galixy ?? (im pretty sure but not 100%)

the 3rd one looks like a elliptical galixy

Explanation:

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18. Compared to its weight on Earth, a 5 kg object on the moon will weigh A. the same amount. B. less. C. more.
s2008m [1.1K]

Answer:

B. less

Explanation:

acceleration due to gravity on Earth, g = 9.8 m/s²

acceleration due to gravity on Moon, g = 1.6 m/s²

Given mass of the object as, m = 5 kg

Weight of an object is given as, W = mg

                                                         

Weight of the object on Earth, W = 5 x 9.8 = 49 N

Weight of the object on Moon, W = 5 x 1.6 = 8 N

Therefore, the object weighs less on the moon compared to its weight on Earth.

The correct option is "B. less"

8 0
4 years ago
A boy drops a coin down a well that is 225 m deep. How long does it take the coin to hit the bottom of the well? please help
Nady [450]
<span>It takes 6.78 seconds for the coin to hit the bottom of the well. We can use the equation h = 0.5gt^2, where h is the height of the coin, g is the gravitational constant of 9.8m/s^2, and t is the time is takes for the coin to hit the bottom of the well. Solve for t to obtain 6.87 seconds.</span>
8 0
3 years ago
How do u convert 7.68 cal/sec to kcal/min
stich3 [128]
<span>First you have to convert 7.68 cal/sec to cal/min to do that, just multiply by 60 So it will be 460.8 cal/min now convert that to kcal/min kcal = kilocalories = 1000 calories. so just divide by 1000 and youll have your answer in kcal/min </span>
5 0
4 years ago
Read 2 more answers
Please help on this one?
DedPeter [7]

The answer is C. Hope this helps.

3 0
3 years ago
Read 2 more answers
A storage tank holds methane at 120 K, with a quality of 25 %, and it warms up by 5°C per hour due to a failure in the refrigera
lord [1]

One of the fundamental pillars to solve this problem is the use of thermodynamic tables to be able to find the values of the specific volume of saturated liquid and evaporation. We will be guided by the table B.7.1 'Saturated Methane' from which we will obtain the properties of this gas at the given temperature. Later considering the isobaric process we will calculate with that volume the properties in state two. Finally we will calculate the times through the differences of the temperatures and reasons of change of heat.

Table B.7.1: Saturated Methane

T_1 = 120K

p_1 = 191.6kPa

v_f = 0.002439m^3/kg

v_{fg} = 0.30367 m^3/kg

Calculate the specific volume of the methane at state 1

v_1 = v_f+x_1v_{fg}

v_1 = 0.002439+ (0.25)(0.30367)

v_1 = 0.0783m^3/kg

Assume the tank is rigid, specific volume remains constant

v_2 = v_1

v_2 = 0.0783m^3/kg

Now from the same table we can obtain the properties,

At v_g = 0.0783m^3/kg

T_2 = 145K

p_2 = 823.7kPa

We can calculate the time taken for the methane to become a single phase

t = \frac{T_2-T_1}{\dot{T}}

Here

T_1 = Initial temperature of Methane

\dot{T} = Warming rate

Replacing

t = \frac{(145-273)-(120-273)}{5}

t = \frac{25}{5}

t = 5hr

Therefore the time taken for the methane to become a single phase is 5hr

5 0
3 years ago
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