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Lapatulllka [165]
3 years ago
14

Which image shows an example of the strong nuclear force in action?

Physics
1 answer:
dusya [7]3 years ago
6 0

i think this is the incomplete page that you are showing but the answer is

:-

<h2><u>B</u></h2>
You might be interested in
A boy 12.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the i
miss Akunina [59]

Answer:

Explanation:

Height covered = 12m

time to fall by 12 m

s = 1/2 gt²

12 = 1/2 g t²

t = 1.565 s

Horizontal distance of throw

= 8.5 x 1.565

= 13.3 m

This distance is to be covered by dog during the time ball falls ie 1.565 s

Speed of dog required = 13.3 / 1.565

= 8.5 m /s

b ) dog will catch the ball at a distance of 13.3 m .

4 0
3 years ago
2. Two cars A and B are heading forward. The velocity of A and B are 30 m/s and 20 m/s
KengaRu [80]

Answer:

A.) 27000 kgm/s

18000 kgm/s

B.) Va = 22 m/s

C.) 19800 kgm/s

25200 kgm/s

Explanation: Given that the velocity of A and B are 30 m/s and 20 m/s. And of the same mass M = 9 × 10^5g

M = 9×10^5/1000 = 900 kg

A.) Initial momentum of A

Mu = 900 × 30 = 27000 kgm/s

Initial momentum of B

Mu = 900 × 20 = 18000 kgm/s

B.) if they have an accident and then the velocity of the B is 28 m/s, find out velocity of A.

Momentum before impact = momentum after impact

Given that Vb = 28 m/s

27000 + 18000 = 900Va + 900 × 28

45000 = 900Va + 25200

900Va = 45000 - 25200

900Va = 19800

Va = 19800/900

Va = 22 m/s

C.) Momentum of A after impact

MV = 900 × 22 = 19800 kgm/s

Momentum of B after impact

MV = 900 × 28 = 25200 kgm/s

8 0
3 years ago
Two laws are described below:
liubo4ka [24]

Answer:

Explanation:

I can conclude that this means that the law can be broken under certain coditions as long as its not focused on a natural phenomonon

and a pheononmono is a fact or situation that is observed to exist or happen, especially one whose cause or explanation is in question.

3 0
3 years ago
Read 2 more answers
7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

v=u+at

where :

v is the final velocity  of the ball

u is the initial velocity

a is the acceleration

t is the time  elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

a=3.5m/s^2 is the acceleration

Solving for t, we find the time taken for this change in velocity:

t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s

Learn more about acceleration:

brainly.com/question/9527152  

brainly.com/question/11181826  

brainly.com/question/2506873  

brainly.com/question/2562700  

#LearnwithBrainly

8 0
3 years ago
As a box slides down a ramp, friction does 23.0 joules of work. At the bottom of the ramp, the box has 3.8 joules of kinetic ene
tensa zangetsu [6.8K]

Answer:

The high of the ramp is 2.81[m]

Explanation:

This is a problem where it applies energy conservation, that is part of the potential energy as it descends the block is transformed into kinetic energy.

If the bottom of the ramp is taken as a potential energy reference point, this point will have a potential energy value equal to zero.

We can find the mass of the box using the kinetic energy and the speed of the box at the bottom of the ramp.

E_{k}=0.5*m*v^{2}\\\\where:\\E_{k}=3.8[J]\\v = 2.8[m/s]\\m=\frac{E_{k}}{0.5*v^{2} } \\m=\frac{3.8}{0.5*2.8^{2} } \\m=0.969[kg]

Now applying the energy conservation theorem which tells us that the initial kinetic energy plus the work done and the potential energy is equal to the final kinetic energy of the body, we propose the following equation.

E_{p}+W_{f}=E_{k}\\where:\\E_{p}= potential energy [J]\\W_{f}=23[J]\\E_{k}=3.8[J]\\

And therefore

m*g*h + W_{f}=3.8\\ 0.969*9.81*h - 23= 3.8\\h = \frac{23+3.8}{0.969*9.81}\\ h = 2.81[m]

8 0
3 years ago
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