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Lapatulllka [165]
3 years ago
14

Which image shows an example of the strong nuclear force in action?

Physics
1 answer:
dusya [7]3 years ago
6 0

i think this is the incomplete page that you are showing but the answer is

:-

<h2><u>B</u></h2>
You might be interested in
Give at least one fact about subatomic particles
victus00 [196]

Answer:

- Particles smaller than atoms are called subatomic particles .

- There are three famous subatomic particles, proton, neutron and electron .

- The study of sub atomic particles are called particle physics

- These particles can be divided as Brayons and Leptons

- These particles are often held together by one of the four fundamental particles ( Weak force, strong force, electromagnetic force, gravitational force).

6 0
3 years ago
A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

7 0
4 years ago
Consider the situation||: A child pulls a sled by a rope across the lawn at a constant speed. Of the forces listed, identify whi
Mice21 [21]

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

6 0
3 years ago
what is the change in the force of gravity between any two bodies when mass of each body is double keeping the distance between
frez [133]

Please find attached photograph for your answer. Do comment if you have any query.. Please do mark me Brainliest if you like my answer

8 0
3 years ago
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.
Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

\sum F=m.a

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N

5 0
3 years ago
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