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nlexa [21]
3 years ago
9

Read this situation : Andres is adding molding to the ceiling in his living room. The room is 20 feet long and 12 feet wide. Wha

t length of molding does he need?
What do you need to operation do you need to do to manipulate this problem?

Area, Perimeter, or Circumference?
Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0
You would need to find the perimeter of the room
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PLEASE HELP, 40 POINTS!!!!!!!!!!!!!!!!!!!
34kurt
Your answer is going to be 7.8m.
6 0
1 year ago
Give the equation of the horizontal asymptote shown below.
Oxana [17]
Polynomial division yields

\dfrac{7x^2}{x^2+5}=7-\dfrac{35}{x^2+5}

As x\to\pm\infty, you have the remainder term approaching 0, so the horizontal asymptote is the line y=7.
4 0
3 years ago
Read 2 more answers
onyango wishes to fence a rectangular research plot using 100 m of wire .one end of the plot has a wall already erected .calcula
earnstyle [38]

Answer:

1250 m²

Step-by-step explanation:

Let x and y denote the sides of the rectangular research plot.

Thus, area is;

A = xy

Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.

Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;

2x + y = 100

Thus, y = 100 - 2x

Since A = xy

We have; A = x(100 - 2x)

A = 100x - 2x²

At maximum area, dA/dx = 0.thus;

dA/dx = 100 - 4x

-4x + 100 = 0

4x = 100

x = 100/4

x = 25

Let's confirm if it is maximum from d²A/dx²

d²A/dx² = -4. This is less than 0 and thus it's maximum.

Let's plug in 25 for x in the area equation;

A_max = 25(100 - 2(25))

A_max = 1250 m²

5 0
3 years ago
PLEASE HELP<br> I have no idea how to do this
tresset_1 [31]

Answer:

1st 2nd or both's answer you want

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2 years ago
How many minutes does the teach
Anastaziya [24]
Assuming that's a 40 minutes a lesson the minutes the tennis teacher teaches in a week is 800 minutes
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