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3 years ago

PLS HELP 20 points and brainliest

2 answers:

8 0

Answer: Since the volume of a cylinder formula involves the radius, you can solve for the radius and double it to find the diameter.

Write the formula. Volume=π⋅radius2⋅height.

Substitute the dimensions of the shape into the formula. Use 3.14 as the value for π. 791.28=3.14⋅r2⋅28.

Solve the equation for the variable.

Step-by-step explanation:

4vir4ik [10]3 years ago

7 0

Answer:Since the volume of a cylinder formula involves the radius, you can solve for the radius and double it to find the diameter.

Write the formula. Volume=π⋅radius2⋅height.

Substitute the dimensions of the shape into the formula. Use 3.14 as the value for π. 791.28=3.14⋅r2⋅28.

Solve the equation for the variable.

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Can someone help with this please!!

Ksenya-84 [330]

Answer:

D) L+S=9 ; 6L+3S=9

Step-by-step explanation:

Given this information, we know that the total number of large and small Ubers must be 9, so we can eliminate choices A and C as the first part of the system of equations is L+S=9

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3 years ago

Find the equation of this line. please help ! anything is appreciated !!

o-na [289]

Answer:

y=3x-4

Step-by-step explanation:

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=

stepan [7]

$\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\
-----------------------------\\\\
recall\quad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)
\\\\\\
now\quad a^2+5a-6\implies (a+6)(a-1)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\
-----------------------------\\\\
$

$\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}$

6 0

3 years ago