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xeze [42]
3 years ago
9

How do you solve -b+b=-4

Mathematics
1 answer:
belka [17]3 years ago
7 0

Answer:

I think the solution to this problem would look like (-8+4).

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A multiplier of 1.641 corresponds to a percentage increase or decrease of what percent?
bezimeni [28]

Answer:

A multiplier of 1.641 corresponds to a percentage increase or decrease of 64.1%.

Step-by-step explanation:

To determine a percentage increase or decrease of a certain number, a calculation consisting of the multiplication of said number by 1 plus the decimals corresponding to the percentage to be increased must be performed. Thus, for example, if you want to increase a number by 50%, you must multiply that number by 1.50. Therefore, if you multiply a number by 1,641, this implies that you are wanting to increase or decrease the initial number by 64.1%.

6 0
3 years ago
What is the value of the 2 in 258,364
Minchanka [31]
200000.........................................................
5 0
2 years ago
The half life of a certain tranquilizer in the bloodstream is 36 hours. How long will it take for the drug to decay to 87% of th
Fudgin [204]

<u>Finding the Decay constant(λ):</u>

λ = 0.693 / (half-life)

we are given that the half-life is 36 hours

λ = 0.693 / (36)

λ = 0.01925 /hour

<u>Time taken for 87% decay:</u>

Since decay is first-order, we will use the formula:

t = \frac{2.303}{decay constant}log(\frac{A_0}{A} )

Where A₀ is the initial amount and A is the final amount

Let the initial amount be 100 mg,

the final amount will be 87% of 100

Final amount = 100*87/100 = 87 mg

<em>Replacing the values in the equation: </em>

<em />t = \frac{2.303}{0.01925}log(\frac{100}{87} )<em />

<em />t = \frac{2.303}{0.01925}*0.06<em />

t = 7.18 hours

<em>We used 'hours' as the unit because the unit of the decay constant is '/hour'</em>

Therefore, the drug will decay to 87% of initial dosage after 7.18 hours

7 0
3 years ago
Where the fine baddies at? hmu
Lady_Fox [76]

Answer:

not here-

Step-by-step explanation:

thanks for the points

6 0
3 years ago
Find the value or values of p in the quadratic equation p2 + 13p – 30 = 0. A. p = 15, p = 2 B. p = –10, p = –3 C. p = 10, p = 3
DENIUS [597]
I hope this helps you




p^2+13p-30=0


p +15


p -2


(p+15)(p-2)=0


p= -15


p=2
7 0
3 years ago
Read 2 more answers
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