Find the commission on a $1,250 sale with a commission rate of 5%.

2 answers:

5 0

Essentially, we must take 5% of $1250. When we drop the percent sign, we move the decimal 2 places to the left, giving .05. Then "of" means multiply. We take $1250 and multiply times .05, giving
$62..50 

Another way to do it is to take 10%, or $125. 
Then 5% is half of that. Half of $125 is $62.50 We can do that by dividing $125 by 2. I did it in my head. Others might do it on paper. Still others might have a calculator handy and say $125 divided by 2 on the calculator. We should all get the same answer unless one person spaces out or is tired. It happens!

GaryK [48]3 years ago

3 0

5% of 1250....turn percent to decimal...." of " means multiply
0.05(1250) = 62.50 <==

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Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$