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hammer [34]
3 years ago
11

Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0
First, factor the (3y-4) and group the remaining terms
y²(3y-4) +7 (3y-4)
(y²+7)(3y-4)
I hope this helps (:
sweet-ann [11.9K]3 years ago
6 0
Dur, so notice we can reverse distribute
ab+ac=a(b+c)


in this case, a=(3y-4)
so
(3y-4)y²+(3y-4)7=(3y-4)(y²+7)
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Alisiya [41]

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Write as<br> logarithm with base 4:<br> 4<br> -5<br> 2<br> -4
NeX [460]

Answer:

log_4(256)=4

log_4(1/1024)=-5

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Step-by-step explanation:

We want to write a number, x, such that

Log_4(y)=x.

In exponential form that is 4^x=y.

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4^4=256 which means log_4(256) is 4 as a logarithm with base 4.

The second number is x=-5.

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8 0
2 years ago
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