Y^2(3y−4) + 7(3y−4) Factor the polynomial as the product of two binomials.
2 answers:
First, factor the (3y-4) and group the remaining terms
y²(3y-4) +7 (3y-4)
(y²+7)(3y-4)
I hope this helps (:
Dur, so notice we can reverse distribute
ab+ac=a(b+c)
in this case, a=(3y-4)
so
(3y-4)y²+(3y-4)7=(3y-4)(y²+7)
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Step-by-step explanation:
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x: -7-2 = -9
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