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kiruha [24]
3 years ago
5

Describe what happens to the electric field lines when two objects with unlike charges are brought near each other.

Physics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

  • <u>Unlike Charges:</u>

The unlike charges attracts each other, as we can say that the two atoms or point charges which posses different properties attracts one another.

Explanation:

  • <u>The electric field lines:</u>

The electric fields shows the direction, the nature, and the magnitude of the charges been placed there in a given space. As the field lines from the positive point charge(+) goes in the outward direction and the negative charges(-) has the field lines coming towards it or they are directed towards inside the test charge.

  • As, the different charges interact lines when interact with one another, the lines become more curved and they slide over the two charges. Now, that is also due to the number of charges attracted toward each present on the surface of the two charges.

<u />

harina [27]3 years ago
4 0
Hello.

The answer is:

It creates a spark.

Then thespark can sometimes start a fire or other serious problems.

Have a nice day
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GPE = mgh

here we have

m = 200 kg

h = 21000 m

now we will have

GPE = 200(9.8)(21000)

GPE = 4.116 \times 10^7 J

so GPE of balloon will be 41160000 J above the given height from ground

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3 years ago
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2 years ago
An atom of uranium 238 emits an alpha particle (an atom of He) and recoils with a velocity of 1.895 * 10^ 5 m/sec . With velocit
lora16 [44]

<u>Answer:</u> The velocity of released alpha particle is 1.127\times 10^7m/s

<u>Explanation:</u>

According to law of conservation of momentum, momentum can neither be created nor be destroyed until and unless, an external force is applied.

For a system:

m_1v_1=m_2v_2

where,

m_1\text{ and }v_1 = Initial mass and velocity

m_2\text{ and }v_2 = Final mass and velocity

We are given:

m_1=238u\\v_1=1.895\times 10^{5}m/s\\m_2=4u\text{ (Mass of }\alpha \text{ -particle)}\\v_2=?m/s

Putting values in above equation, we get:

238\times 1.895\times 10^5=4\times v_2\\\\v_2=\frac{238\times 1.895\times 10^5}{4}=1.127\times 10^7m/s

Hence, the velocity of released alpha particle is 1.127\times 10^7m/s

4 0
3 years ago
How much Tim in minutes will it take a car driving at 90km/hr to travel 27 kilometers
astraxan [27]

Answer:

18min

Explanation:

v=d/t

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Read 2 more answers
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