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Cerrena [4.2K]
3 years ago
15

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a s

mooth, horizontal surface with no friction. The mass is pulled away from the equilibrium position by a distance A in the positive x-direction and then released so that it oscillates in simple harmonic motion with frequency f. What will happen to the frequency of the oscillation if the mass is doubled?
Physics
1 answer:
Alenkinab [10]3 years ago
6 0

Explanation:

The frequency of a spring is:

f = 1/(2pi) sqrt(k / m)

If m doubles, then f decreases by a factor of 1/sqrt(2).

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A steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.the speed of transverse waves on the wire would be  372.77 m/s

<h3>What is a sound wave?</h3>

It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.

For calculating the wave velocity of the sound waves generated from the piano can be calculated by the formula

V= √F/μ

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F is the tension in the string of piano

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As given in question a steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.

The μ is the mass per unit length of the string would be

μ = 4.80/(1.150×1000)

μ = 0.0041739 kg/m

By substituting the respective values of the tension on the string and the density(mass per unit length) in the above formula of the wave velocity

V= √F/μ

V=√(580/0.0041739)

V =  372.77 m/s

Thus,  the speed of transverse waves on the wire comes out to be  372.77 m/s

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