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Cerrena [4.2K]
3 years ago
15

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a s

mooth, horizontal surface with no friction. The mass is pulled away from the equilibrium position by a distance A in the positive x-direction and then released so that it oscillates in simple harmonic motion with frequency f. What will happen to the frequency of the oscillation if the mass is doubled?
Physics
1 answer:
Alenkinab [10]3 years ago
6 0

Explanation:

The frequency of a spring is:

f = 1/(2pi) sqrt(k / m)

If m doubles, then f decreases by a factor of 1/sqrt(2).

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You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee
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V = 4.81 V

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