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Cerrena [4.2K]
3 years ago
15

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a s

mooth, horizontal surface with no friction. The mass is pulled away from the equilibrium position by a distance A in the positive x-direction and then released so that it oscillates in simple harmonic motion with frequency f. What will happen to the frequency of the oscillation if the mass is doubled?
Physics
1 answer:
Alenkinab [10]3 years ago
6 0

Explanation:

The frequency of a spring is:

f = 1/(2pi) sqrt(k / m)

If m doubles, then f decreases by a factor of 1/sqrt(2).

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Answer:

It wouldn't be 9am in New York because San Francisco is 3 hours behind of New York

Explanation:

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A salt shaker sits 0.102 m from
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The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

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where the term on the left is the frictional force and the term on the right is the centripetal force, and where

\mu_s is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

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In this problem, we have:

\mu_s = 0.307

r = 0.102 m

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Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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4 years ago
Who discovered natural magnet for the first time?​
andrew-mc [135]
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3 years ago
A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm
Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

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c=3.0\cdot 10^8 m/s

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

d=vt (1)

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t=5\cdot 10^{-5}s

d=2L, where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m

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