That would be true because a solid object can cast a shadow
Answer:
The equilibrium position will shift towards the left hand side or reactants side
Explanation:
Decreasing the volume (increasing the pressure) of the system will shift the equilibrium position towards the lefthand side or reactants side. This is because, decreasing the volume (increasing the pressure) implies shifting the equilibrium position towards the side having the least number of moles.
There are two moles of reactants and a total of three moles of products(total). Hence decreasing the volume and increasing the pressure of the gas phase reaction will shift the equilibrium position towards the lefthand side.
Answer:
<h3>a.</h3>
- After it has traveled through 1 cm :
- After it has traveled through 2 cm :
<h3>b.</h3>
- After it has traveled through 1 cm :
- After it has traveled through 2 cm :
Explanation:
<h2>
a.</h2>
For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient the formula is:
where I is the intensity of the beam, is the incident intensity and x is the length of the material traveled.
For our problem, after travelling 1 cm:
After travelling 2 cm:
<h2>b</h2>
The optical density od is given by:
.
So, after travelling 1 cm:
After travelling 2 cm:
The domains in a magnet are aligned according to magnetic fields.