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3 years ago

Do all of our scientific instruments have a limit on how precise they can make a measurement?

Physics

1 answer:

vladimir2022 [97]3 years ago

8 0

Yes. that is "True".

All instruments have limited exactness, so the capacity to determine little contrasts in measurement is subsequently restricted.

Precision alludes to the closeness of at least two estimations to one another. For example, on the off chance that you gauge a given substance five times, and get 3.2 kg each time, at that point your estimation is precise. You can be extremely precise yet mistaken. You can likewise be exact yet not precise.

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When we see a meteor shower, it means that ________.

Irina18 [472]

Answer:

option A

Explanation:

The meteor shower is the celestial activity in which meteors are observed to radiate or originate from one point.

Meteors are nothing but dust or ice from the trails of comets. Most of the meteors are less than the size of the sand particle.

We will see comet shower when we earth will cross the orbit of the comet.

Hence, the correct answer is option A

6 0

4 years ago

What is the speed of a wave in (m/s) with a 5 meter wavelength and a period of 20 seconds?

arlik [135]

Answer: 0.25 m/s

Explanation: Speed = wavelengt · frequency

v = λf and frequency is 1/period f = 1/T

Then v = λ/T = 5 m / 20 s = 0.25 m/s

6 0

3 years ago

A car, initially traveling 28.0ft/s, steadily speeds up to 44.0ft/s in 4.50s. Determine all unknowns and answer the following qu

dexar [7]

Explanation:

hi do u mind helping me with something lmak

5 0

3 years ago

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground

Setler79 [48]

They will both hit the ground at the same time because gravitational acceleration for all objects is the same.

6 0

4 years ago

A cannon fires a cannonball forward at a velocity of 48.1 m/s horizontally. If the cannon is on a mounted wagon 1.5 m tall, how

GalinKa [24]

Answer: 473.640 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the travel of the cannonball has two components: x-component and y-component. Being their main equations as follows:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=48.1 m/s$ is the cannonball's initial velocity

$\theta=0$ because we are told the cannonball is shot horizontally

$t$ is the time since the cannonball is shot until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=1.5m$ is the initial height of the cannonball

$y=0$ is the final height of the cannonball (when it finally hits the ground)

$g=9.8m/s^{2}$ is the acceleration due gravity

We need to find how far (horizontally) the cannonball has traveled before landing. This means we need to find the maximum distance in the x-component, let's call it $X_{max}$ and this occurs when $y=0$ .

So, firstly we will find the time with (2):

$0=1.5 m+48. 1 m/s sin(0\°) t-(4.9 m/s^{2})t^2$ (3)

Rearranging the equation:

$0=-(4.9 m/s^{2})t^2+48. 1 m/s sin(0\°) t+1.5 m$ (4)

$-(4.9 m/s^{2})t^2+(48. 1 m/s) t+1.5 m=0$ (5)

This is a <u>quadratic equation</u> (also called <u>equation of the second degree</u>) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: