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enot [183]
3 years ago
10

Marissa can but 3 oranges for $1.35, 4 oranges for $1.80, or 5 oranges for $2.25. Marissa can buy 10 oranges for a price that fi

ts this pattern or a bag of 10 oranges for $4.25. which way costs less for 10 oranges?explain
Mathematics
1 answer:
nikklg [1K]3 years ago
7 0
From 3 oranges to 4 oranges, you're adding 45¢. Therefore, 1 orange is 45¢. You can then multiply 45 by 10 to get 450¢, which is $4.50. $4.25 is less than $4.50, so not following the pattern is cheaper. Hope this helps!
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A survey of 600 randomly selected high school students determined that 290 play organized sports. what is the probability that a
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Answer:

29/60

Step-by-step explanation:

probability of playing is 290/600 which when simplified is29/60

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2 years ago
Question in the picture below. (30 points)
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Answer:

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3 years ago
What is the value of the expression, written in standard form? (6.6x10^-2)/(3.3x10^-4)
Eduardwww [97]
0.066/0.00033
The answer is 200.
4 0
3 years ago
Read 2 more answers
Mair of angles is classified in the same category according to the angle measure?<br> h
Norma-Jean [14]
You just started a new job with a salary of $37,440 a year ($18 an hour).
With an expected rent payment of 25% - 30% of your gross monthly income, find 5 apartments
that you can choose from in any city or town in The United States. Your move in date is on June
12th. 2022.
Answer the following questions:
1. What is your rental range per month (up to 30% of your gross monthly income)
2. What amenities do you want/need (# of bedrooms/ bathrooms, washer/dryer, pets
allowed etc....)
3. List your 5 apartments, with cost of rent.
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4 0
2 years ago
Which is the solution set to the inequality (4x-3)(2x-1)&amp;gt=0?
Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0         2x - 1 = 0

x = \frac{3}{4}               x = \frac{1}{2}

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------\frac{1}{2}------\frac{5}{8}------\frac{3}{4}------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1]  = ( - )( - ) = +  THIS WORKS!

Test Point \frac{5}{8}: [4(\frac{5}{8}) - 3][2(\frac{5}{8}) - 1]  = ( - )( + ) = -  <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1]  = ( + )( + ) = +  THIS WORKS!

Answer: x ≤ \frac{1}{2}   or   x ≥ \frac{3}{4}

Interval Notation: (-∞, \frac{1}{2}] U [\frac{3}{4}, ∞)

Graph: ←------\frac{1}{2}          \frac{3}{4}--------→

5 0
3 years ago
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