Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
- 1/4
- 3/5
Step-by-step explanation:
You find the part by expressing the ratio as a fraction, then simplifying.
1. 5/20 = (1·5)/(4·5) = (1/4)·(5/5) = 1/4
5 is 1/4 of 20.
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2. 12/20 = (3·4)/(5·4) = (3/5)·(4/4) = 3/5
12 is 3/5 of 20.
Answer:
X is 90 y is 43
Step-by-step explanation:
Answer:
the answer to your question is 'b'
Answer:
100
Step-by-step explanation:
120 + 130 + 10 = 260
360 - 260 = 100
