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Vladimir79 [104]
3 years ago
10

Need help!!!!!!!!!!!!!!

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
It is the last answer that is the correct one 

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Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

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3 years ago
Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than 4/5 of Terrance’s score. If t rep
hram777 [196]
77 \geq 5 + 4/5t
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