Answer:
Explanation:
p(i)*v(i)/t(i)=p(f)*v(f)/t(f)
plug and chug
There are 1.22 grams of He in the mixture. The mixture contains 0.304 moles of He, 0.250 moles of N2 and 0.250 moles of O2. Since the mixture of gases are at standard temperature and pressure, the total moles of the mixture equivalent to 18.0 L is 0.804 moles.
Further Explanation:
At standard temperature and pressure of 0°C and 1.00 atm, the molar volume of gas is 22.4 L.
From this, the total moles of the mixture can be derived using the solution below:
Therefore, the total moles of gases in an 18.0 L mixture at STP is:
By algebra, the moles of He may be solved using the given moles of the other two gases: 0.250 mol N2 and 0.250 mol O2.
0.304 moles of He is equal to 1.22 grams of He.
Learn More:
- Learn more about Boyle's Law brainly.com/question/12968820
- Learn more about Gay-Lussac's Law brainly.com/question/6534668
- Learn more about Ideal Gas Law brainly.com/question/12935899
Keywords: molar volume, STP, stoichiometry
Answer:
The correct answer is - hard water reacts to form the calcium or magnesium salt of the organic acid of the soap.
Explanation:
Soaps are made up of fatty acids or oils by treating with strong alkali and are salts of sodium and potassium. Hard water, on the other hand, has a high concentration of minerals in comparison to soft water. When hard water and soap are mixed together the salts of the minerals like Ca2+ and Mg2+ ions present in hard water react with fatty acids of the soap.
The sodium salts are changed to the salts of calcium and magnesium which are precipitated to an insoluble substance. The insoluble salts of the calcium or magnesium dirt stick on the clothes thus cleaning ability of soap is reduced.
Answer : The correct option is,
Explanation :
Molar mass : It is defined as the mass of the substance in grams or kilograms present in the one mole of substance.
The unit of molar mass is, gram/mole or g/mol.
Given : Molar mass of = 44.01 g/mole
That means, one mole of contains 44.01 gram of .
Answer:
Percentage of carbon of alkene is higher compared to the alkane that has the same number of carbon per molecule. Because of this, combustion of alkene will produce more sooty flame compared to their corresponding alkane and because Alkenes have a higher percentage of carbon compared to their corresponding alkane.
Explanation:
Relative atomic mass : C= 12 and H=1
Percentage of Carbon Hexane (C6H14)
Percentage of Carbon = 83.7 percent
6(12) x 6(12) +14(1) x 100 percent= 83.7 percent
Percentage of Carbon Hexene = 85.7 percent