Answer: 167 g
Explanation:
1) The depression of the freezing point of a solution is a colligative property ruled by this equation:
ΔTf = i × m × Kf
Where:
ΔTf is the decrease of the freezing point of the solvent due to the presence of the solute.
i is the Van't Hoof factor and is equal to the number of ions per each mole of solute. It is only valid for ionic compounds. Here the solute is not ionice, so you take i = 1
Kf is the molal freezing constant and is different for each solvent. For water it is 1.86 m/°C
2) Calculate the molality (m) of the solution
ΔTf = i × m × Kf ⇒ m = ΔTf / ( i × Kf) = 5.00°C / 1.86°C/m = 2.69 m
3) Calculate the number of moles from the molality definition
m = moles of solute / kg of solvent ⇒ moles of solute = m × kg of solvent
moles of solute = 2.69 m × 1.00 kg = 2.69 moles
4) Convert moles to grams using the molar mass
molar mass of C₂H₆O₂ = 62.07 g/mol
mass in grams = number of moles × molar mass = 2.69 moles × 62.07 g/mol = 166.97 g ≈ 167 g
Answer:
68g/mol
Explanation:
The formula of ammonium sulfide is:
Ammonium sulfide = (NH₄)₂S
The molar mass of a compound is the mass in gram of one mole of the substance. In a compound, it is expressed gram formula mass or gram-molecular weight.
It is determined by the addition of the component atomic masses and then expressed in grams;
Atomic mass of N = 14, H = 1 and S = 32
(NH₄)₂S = 2[14 + 4(1)] + 32 = 36 + 32 = 68g/mol
Answer:false you are welcome
Explanation:
Answer:
(−ΔH°1)+12(−ΔH°2)+(ΔH°3)+(ΔH°4)
I hope this helps you out!! :)
Answer:
10 g of powered sugar
Explanation:
The powered sugar will have more surface are for the solvent to dissolve faster
