The amount, in grams, of ethanol needed to prepare 268 grams of a 9.76 M solution of ethanol in water will be 120.50 grams
<h3>Solution preparation</h3>
In order to prepare 268 grams of solution, 268 mL of water would be needed because 1 mL of water weighs 1 gram.
Since we now know the volume of solution that we want to prepare, the amount of solute (ethanol) that would be required in order to make a solution of 9.76 M will be:
Mole required = 9.76 x 268/1000 = 2.62 moles
Mass of 2.62 moles ethanol = 2.62 x 46.07 = 120.50 grams
More on solution preparation can be found here: brainly.com/question/14667249
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Explanation:
The given data is as follows.
, ![T_{h} = 350^{o}C](https://tex.z-dn.net/?f=T_%7Bh%7D%20%3D%20350%5E%7Bo%7DC)
Work produced per kJ of heat extracted from hot reservoir = 0.45 kJ = Efficiency
If the device is Carnot cycle then its efficiency will be maximum and its value will be equal to ![[1 - (\frac{T_{c}}{T_{h}} )]](https://tex.z-dn.net/?f=%5B1%20-%20%28%5Cfrac%7BT_%7Bc%7D%7D%7BT_%7Bh%7D%7D%20%29%5D)
Using this relation we will calculate the efficiency as follows.
Efficiency = ![[1 - (\frac{T_{c}}{T_{h}} )]](https://tex.z-dn.net/?f=%5B1%20-%20%28%5Cfrac%7BT_%7Bc%7D%7D%7BT_%7Bh%7D%7D%20%29%5D)
=
= 0.928
Hence, it means that this type of device is possible and the claim is also believable.
The total ball pressure is sum of gauge pressure and atmospheric pressure
We know that atmospheric pressure = 101.325 kPa
so the total ball pressure = 61 kPa + 101.325 kPa = 162.325 kPa
Now we will use ideal gas equation as
PV = nRT
P = pressure = 162.325 kPa
V = 5.2 L
R = gas constant = 8.314 kPa L / mol K
T = 32 C = 273.15 + 32 = 305.15 K
n = moles = ?
Moles = PV / RT = 162.325 kPa X 5.2 / 305.15 X 8.314 = 0.332 moles
13 is the number for it on the periodic table and Group 3 is the correct answer hope this helps.