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labwork [276]
4 years ago
8

Hexane and hexene are hydrocarbon compounds from different homologous series. the combustion of these two compounds produce diff

erent amount of soot. explain the difference based on the percentage of carbon by mass.
Chemistry
1 answer:
AURORKA [14]4 years ago
7 0

Answer:

Percentage of carbon of alkene is higher compared to the alkane that has the same number of carbon per molecule. Because of this, combustion of alkene will produce more sooty flame compared to their corresponding alkane and because Alkenes have a higher percentage of carbon compared to their corresponding alkane.

Explanation:

Relative atomic mass : C= 12 and H=1

Percentage of Carbon Hexane (C6H14)

Percentage of Carbon = 83.7 percent

6(12) x 6(12) +14(1) x 100 percent= 83.7 percent

Percentage of Carbon Hexene = 85.7 percent

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The solution for this problem is:
Let x = speed of wind

Speed of plane with the wind = x + 100

Speed of plane against the wind = 100 -x 

 We will be using the formula for distance which is (Rate)(Time), getting the formula for time would be distance/rate Time to travel 600 miles with the wind = Time to travel 400 miles against the wind 600/(x + 100) = 400/(100 - x)

 400(x + 100) = 600(100 - x)

 400x + 40000 = 60000 - 600x

 1000x = 20000

x = 20000/1000

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4 years ago
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The nh2cl model consists of balls and sticks. the electrons in the molecule are paired, and each stick represents a valence elec
tangare [24]

Valence electrons in NH2Cl:

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So there are 14 valence electrons in NH2Cl

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And for 7 valence electron pairs, 7 sticks needed.

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3 years ago
suppose the heat of neutralization had ben determined using a glass beaker instead of a polystyrene coffee​ cup.how would the me
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3 years ago
A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]
Mnenie [13.5K]

<u>Answer:</u> The hydronium ion concentration in the solution is 1.29\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M

The chemical reaction for aniline and HCl follows the equation:

                   C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-

<u>Initial:</u>           0.24          0.060              0.31

<u>Final:</u>             0.18          -                     0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})

pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of benzoic acid = 4.2

[C_6H_5COO^-]=0.18M

[C_6H_5COOH]=0.37M

pH = ?

Putting values in equation 1, we get:

pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89

To calculate the hydronium ion concentration in the solution, we use the equation:

pH=-\log[H_3O^+]

pH = 3.89

Putting values in above equation, we get:

3.89=-\log[H_3O^+]

[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M

Hence, the hydronium ion concentration in the solution is 1.29\times 10^{-4}M

3 0
3 years ago
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