Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
We know, sum of all the angles in a triangle is equal to 180 degree
So, 90 + 2x + 3x = 180
5x = 180-90
x = 90/5
x = 18
∠ANB = 2x = 2(18) = 36
∠BNC = 3x = 3(18) = 54
Hope this helps!
Answer:
y=-3
Step-by-step explanation:
31=4-9y
9y=4-31
9y=-27
y=-27/9
y=-3
Answer: -1/6
Step-by-step explanation:
slope= change of y over change of x
3-4/ 5--1=
-1/6
Hope this helps!
Answer:
339416
Step-by-step explanation:
848,540 * 40/100 = 339416
