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marysya [2.9K]
3 years ago
5

PPPPPPPPPPPPPLLLLLLLLLLLLLLZZZZZZZZZZZZZZZ HELP!!!!!!!!! A. B. C. D.

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

The answer is D.16

Step-by-step explanation:

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Find the GCF of each set of numbers.<br> 64, 32 PLEASE Help
likoan [24]

Answer:

32

Step-by-step explanation:

32 is the greatest factor for 32 and 64

5 0
3 years ago
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Simplify the expression to a + bi form:<br> (3 - 2i)(-10 - 7i)
MAXImum [283]

Answer:

(3 - 2i)( - 10 - 7i) \\  =  - 30 - 21i + 20i + 14 {i}^{2}  \\  =  - 30 - i - 14 \\  =  - 44 - i

I hope I helped you^_^

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3 years ago
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Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu
Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

  • Cada manzana cuesta $3.
  • Cada pera cuesta $1.

-----------------------

  • Un sistema de ecuaciones soluciona esta pergunta.
  • El custo de una manzana es x.
  • El custo de una pera es y.

-----------------------

  • <u>Seis manzanas y 8 peras cuestan $26</u>, o sea, 6x + 8y = 26
  • <u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

6x + 8y = 26

6(3y) + 8y = 26

18y + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y = 3(1) = 3.

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

6 0
3 years ago
Factor the trinomial by guess and check<br><br> 2c^2 - 14c+20
Olenka [21]

2c^2-14c+20=0 \\ c^2-7c+10=0 \\ (c-2)(c-5)=0 \\ c_1=2,c_2=5.

8 0
3 years ago
The ordered pairs ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4 ) , ( 4 , 2 5 6 ) , ( 5 , 1 , 0 2 4 ) ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4
Annette [7]

Answer:

The rule is f(x) = 2^(2x).

Step-by-step explanation:

Note that 4 = 2^2, 16 = 4^2,  64 = 8^2, 256 = 16^2  and 1024 = 32^2

and the first numbers in the ordered pairs are 1 , 2 ,3, 4, 5

compare this with  2, 4 , 8, 16 , 32.

We see that the rule for this is 2^x  where x is the sequence number.

So the rule for the original ordered pairs is (2^x)^2.

= 2^2x.

3 0
3 years ago
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