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3 years ago

What is mode mean median ?

Mathematics

1 answer:

amid [387]3 years ago

8 0

Answer:

Mode is the most common

Median is the middle number when put in order of smallest to biggest

Mean is where you added them all up and divide by how many there is

Step-by-step explanation:

5, 7, 6, 7, 10

The median of these numbers is 7

The mode is 7

The mean is also 7 (5+6+7+7+10=35 35÷5=7)

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What is A square + B square

OleMash [197]

Answer: c square

This formula is called Pythagorean theorem

Do you want me to do an entire 9 weeks of online school for you?

Step-by-step explanation:

6 0

3 years ago

Solve by substitution <br> X^2= 2y + 10<br> 3x-y = 9

Viefleur [7K]

Answer:

$x=-4\\ x=-2\\ y=-21\\ y=-15$

Step-by-step explanation:

$x^{2} =2y+10$

$y=-9+3x$

$x^{2} =2(-9+3x)+10$

$x^{2} =-18+6x+10$

$x^{2} =6x-8$

$x^{2} -6x+8$

$x=-4, -2$

$y=-9+3(-4)$

$y=-9-12$

$y=-21$

$y=-9+3(-2)$

$y=-9-6$

$y=-15$

8 0

4 years ago

Read 2 more answers

Hey can you please help me posted picture of question

Ronch [10]

The formulas for conditional probability are:
$P(A\cap B')=P(A)\cdot P(B'|A)$
$P(A\cap B')=P(B')\cdot P(A|B')$ .
Since $P(A\cap B')= \frac{1}{6}$ and $p(B')= \frac{7}{18}$ , you have the equation $\frac{1}{6} = \frac{7}{18} \cdot P(A|B')$ .
Therefore, $P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}$ .
Answer: The correct choice is D.

8 0

3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

In a transformation, the final figure is called.

Viktor [21]

Answer:

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation.

6 0

3 years ago