Question

What is (x+5)(x-4)=0 Expand and solve for x

Answer 1

Answer:

A) $\huge\boxed{\sf x^2 + x - 20 = 0}$

B) $\huge\boxed{\sf x = - 5 \ \ \ \ OR \ \ \ \ x = 4}$

Step-by-step explanation:

$\sf (x+5)(x-4) = 0$

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Expanding:

Expanding Brackets

$\sf x^2 -4x+5x-20 = 0$

Adding / Subtracting Like terms

$\sf x^2 + x - 20 = 0$

$\rule[225]{225}{2}$

Solving:

Given the equation:

(x+5)(x-4) = 0

Using zero Method

Either,

x + 5 = 0   OR      x - 4 = 0

x = - 5       OR       x = 4

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Answer 2

step 1

(x - 4) • (x + 5) = 0

STEP

:

A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

Solving a Single Variable Equation:

2.2 Solve : x-4 = 0

Add 4 to both sides of the equation :

x = 4

Solving a Single Variable Equation:

2.3 Solve : x+5 = 0

Subtract 5 from both sides of the equation :

x = -5

.