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Alexxx [7]
4 years ago
7

What is the value of y?

Mathematics
2 answers:
Ludmilka [50]4 years ago
5 0
Y=35 with working shown in the photo

Rudik [331]4 years ago
3 0

Answer:

Step-by-step explanation:

You'll start by finding the opposite angle of 104

180-104= 76

Then you'll get the triangular equation (keep in mind that a triangle's angles always add up to 180)

180 = 76 + (2y - 1) + y

following the poperties of equality you should get y = 35

Hope this helps :)

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Dima020 [189]
I think the answer is 10 i am not sure

4 0
4 years ago
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Can someone tell me what is 6=2(y+2)
tatuchka [14]

Distribute the 2 through the parentheses

on the right side of the equation.

2(y) is 2y and 2(2) is 4.

So the problem now reads 6 = 2y + 4.

Now we can subtract 4 from both

sides of the equation to get 2 = 2y.  

Now divide both sides of the

equation by 2 and <em>1 = y</em>.

8 0
4 years ago
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Is 4.565656.... Rational or Irrational
ELEN [110]

Answer:

Rational

Step-by-step explanation:

4.5656565656... can be turned into a fraction. The number is a repeating decimal. Repeating decimals are rational numbers.

4.5656565656... = 4\frac{56}{99}

Hope this helps.

8 0
4 years ago
A basketball player is 7 ft tall. He shoots the ball into the basket and the path of the
emmainna [20.7K]

Answer:

52

Step-by-step explanation:

Given the the equation h(t) =-15t^2+ 30t+7 where t is the time in second

So to find the ball's maximum height we can apply the vertex formula:

t= \frac{-b}{2a}  

to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".

Standard quadratic form is: ax^2+bx+c

=> a=15, b=30 in our given equation

<=> t = \frac{-30}{2*-15} =1

When t =-1 we have h(t) = 15*1^2+ 30*1+7 = 52

So the ball's maximum height is:  52

Hope it will find you well.

6 0
3 years ago
A rectangle with vertices (3,-2),(3,-4), (7, -2), (7, -4) is reflected across the x-axis and then rotated 90° counterclockwise.
BigorU [14]

Answer: A reflection about the y-axis and a clockwise rotation of 90° around the origin.

another example is:

A counterclockwise rotation of 90° around the origin, and then a reflection about the y-axis.

Step-by-step explanation:

Let's do this for a single point because it is essentially the same.

Let's use the point (3, -2)

First, we have a reflection across the x-axis, this only changes the sign of the y-component.

Then the new point will be: (3, -(-2)) = (3, 2)

Notice that this point is on the first quadrant.

Now we do a 90° counterclockwise rotation.

Then we move to the second quadrant, and we change the order of the components in the point (and because we are in the second quadrant, the x-component is negative and the y-component is positive)

Then the new point is (-2, 3)

Now, another transformation that is equivalent to this one is to do first a reflection about the y-axis, so we only change the sign of the y-component

Then the new point is (-3, -2)

And now we are in the third quadrant.

and then we do a rotation of 90° clockwise, which moves our point to the second quadrant, changes the order of the components and leaves the y-component positive and the x-component negative, then the new point is:

(-2, 3)

Same as before.

(notice that we used the same transformations, but applied to different line and direction of rotation)

Another example is if we first start with a counterclockwise rotation of 90° around the origin, the original point (3, -2) is on the fourth quadrant, so this rotation leaves our point in the first quadrant, so we change the order of the components and both of them will have a positive sign.

The new point is: (2, 3)

Now let's do a reflection about the y-axis, which changes the sign of the x-component.

Then the final point is (-2, 3), same as before.

And there are a lot of other transformations that will be equivalent to this ones, these are just two examples.

3 0
3 years ago
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