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Sauron [17]
3 years ago
10

Solve the equation. 10y2 – 17y + 12 = y + 16

Mathematics
1 answer:
Deffense [45]3 years ago
5 0

10y2 - 17y + 12 = y + 16

10y2 - 17y + 12 - 16 = y

10y2 - 17y - 4 = y

10y2 -17y - y -4 = 0

10y2 -16y - 4 = 0

Now put formula

x = -b +- (square root) b2 - 4ac

                  2a

a = 10 b= -16 c= -4

y = -(-16) +- (square root) -16 - 4 (10) (-4)

                              2(10)

y = 16 +- (square root) -16 - 400

                                 20

y = 16 +- (square root) -416

                          20

y = 16 +- 20.396

               20

Now this +- is the plus minus thingy in which two answers come

The first we will do is +

16 + 20.396                                         16 - 20.396

   20                                                             20

= 1.8198                                                           = -0.2198

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Alinara [238K]
First to solve the inequality 
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7 0
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BARSIC [14]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity:  cos 2A = 2cos²A - 1

Use the Difference Identity:  cos (A - B) = cosA · cosB + sinA · sinB

Use the Unit Circle to evaluate:  cos (π/2) = 0   &     sin (π/2) = 1

<u>Proof  LHS → RHS</u>

\text{Given:}\qquad \qquad \qquad \qquad 2\cos^2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)-1\\\\\\\text{Double Angle Identity:}\quad \cos2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)\\\\\\\text{Simplify:}\qquad \qquad \qquad \quad \cos\bigg(\dfrac{\pi}{2}-A\bigg)\\\\\\\text{Difference Identity:}\qquad \cos\dfrac{\pi}{2}\cdot \cos A+\sin \dfrac{\pi}{2}\cdot \sin A\\\\\\\text{Unit Circle:}\qquad \qquad \qquad 0\cdot \cos A+1\cdot \sin A\\\\\\\text{Simplify:}\qquad \qquad \qquad \qquad \sin A

LHS = RHS:   sin A = sin A   \checkmark

 

4 0
4 years ago
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In short, Your Answer would be 12 mm

Hope this helps!
3 0
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