Question

Write the equation of a line in slope-intercept form that is parallel to the given line and passes through the point (12,-25).

Answer 1

Answer:

$m_1 = m_2 = \frac{1}{4}$

And then since the new equation have the following form:

$y = m_2 x +b$

We can use the point given (x=12, y = -25) in order to find the intercept with this equation:

$-25 = \frac{1}{4} (12) +b$

And solving for the intercept b we got:

$-25 = 3 +b$

We subtract in both sides 3 and we got:

$b = -25-3 = -28$

And our final equation who satisfy the condition given is:

$y= \frac{1}{4} x -28$

Step-by-step explanation:

For this case we have the following equation given:

$y = \frac{1}{4} x + 2$

And we want to find an equation of a line parallel to the given function and this case we need to satisfy this condition:

$m_1 = m_2 = \frac{1}{4}$

And then since the new equation have the following form:

$y = m_2 x +b$

We can use the point given (x=12, y = -25) in order to find the intercept with this equation:

$-25 = \frac{1}{4} (12) +b$

And solving for the intercept b we got:

$-25 = 3 +b$

We subtract in both sides 3 and we got:

$b = -25-3 = -28$

And our final equation who satisfy the condition given is:

$y= \frac{1}{4} x -28$