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3 years ago

Hi what is the answer for this please

Mathematics

2 answers:

masha68 [24]3 years ago

7 0

Answer:

Step-by-step explanation:

const2013 [10]3 years ago

3 0

It was reflected over the x axis

That's all I see

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Identify the graph of the inequality 2(2x-1)+7<13 or-2x + 5≤-10.

xxMikexx [17]

Answer:

Step-by-step explanation:

(

−

)

Expand LHS

→

−

Divide through by

→

is represented on the real line by the interval

(

−

∞

)

This can be represented on the

−

plane by the area to the left of the vertical line

as graph below.

graph{2(2x-1)+7<13 [-10, 10, -5, 5]}

5 0

1 year ago

If MNO IS NMO what statement best describes triangle MON?

kirill [66]

If , what statement best describes triangle MON?

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3 years ago

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What is the value of the expression?

Morgarella [4.7K]

13.23 is the answer for that equation

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3 years ago

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What is 1 1/2 cm. in km.

Aleonysh [2.5K]

Ok is easy first it takes 10mm =1cm 100cm=1m 1000mm=1km so you do 1.5 divided by 1000km=.0015 km so your answer is .0015km

8 0

3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago