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fredd [130]
3 years ago
7

Which set only contains numbers that make the inequality true?

Mathematics
2 answers:
pashok25 [27]3 years ago
5 0

Answer:

A

Step-by-step explanation:

3 + 19 = 22

4 + 19 = 23

5 + 19 = 24

6 + 19 = 25

All sums are less than 28

blsea [12.9K]3 years ago
3 0

Answer:

A)

Step-by-step explanation:

x < 9

all numbers less than 9 make the inequality true

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DedPeter [7]

Answer: 1 1/14

Step-by-step explanation:

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Step-by-step explanation:

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hope this helps :D

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3 years ago
What is the slope of y = -4
atroni [7]

Answer:

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3 years ago
Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
2 years ago
The area of a trapezoid is given by the formula A=h/2(a+b) .<br><br> Solve the formula for b.
Komok [63]

Answer:

(2A)/h -a =b

Step-by-step explanation:

A= [h(a+b)]/2       I rewrote the formula, because h and a+b are in the numerator.

2A=h(a+b)  Multiply both sides of equation by 2

(2A)/h= a+b Divide both side by h

(2A)/h -a= b Subtract a from both sides

4 0
3 years ago
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