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3 years ago

I am a decimal

2 answers:

6 0

0.6<2x<0.65 (because it's closer to 6)
0.3<x<0.325

Since the thousandths digit of 2x is 2, then the thousandths digit of x is 1 or 6, so the decimal could be 0.301, 0.302, 0.311, 0.312, 0.321

Hope this helps :)

fenix001 [56]3 years ago

3 0

Numbers greater than 0.3 and less then 0.35 are between .6 and .7 when doubled.

Lets assume it is a decimal that goes up to the thousandths.
0.310 to 0.324 Would be closer to .6 than .7. We know the thousands digit has to be a 1 or a 6 because its double ends in a two. So it looks like our options are .311, .316 and .321.

You might be interested in

Four streets enter a traffic circle at points A B C and D name six arcs formed by the streets.

lilavasa [31]

Arcs are just sections of the circle
so lets say you had a pizza

and you put some points on the crust, the legnth of the crust from point to point is that arc

example
if you put poins A and B, then arc AB is the crust between points A and B

arcs can include other points as well
and arc AB=arc BA

so
I wil name easy arcs first
arc AB
arc BC
arc CD
ard DA

now ones that include others
arc AC
arc BD

so the arcs you might want to list are

arc AB
arc BC
arc CD
ard DA
arc AC
arc DB

5 0

3 years ago

Thank you guys so much

jeka57 [31]

Answer:

B. City P is above sea level and City R is below sea level

Step-by-step explanation:

A. City R is negative meaning it is below sea level however City Q is 0 meaning it is at sea level, so this statement is false.

C. Once again, City P is positive meaning it is above sea level but City Q is 0 meaning it is at sea level, so this statement is false.

D. Like before, City P is above sea level and City Q is at sea level not below, so this is, once again, false.

6 0

3 years ago

According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou

Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

$p=X/n=35/140=0.25$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239$

We calculate the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198$

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

$P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183$

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

$p=X/n=21/140=0.15$

We can calculate then the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906$

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

$P(X$

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231$

We can calculate the z-scores for p1=0.18 and p2=0.25:

$z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651$