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8090 [49]
3 years ago
15

A right triangle has side lengths a, b and c as shown below. Uses these lengths to find tan x, cos x, and sin x.

Mathematics
1 answer:
puteri [66]3 years ago
4 0

Answer:

See Below

Step-by-step explanation:

Tan is the ratio of "opposite" side to "adjacent side

Cos is the ratio of "adjacent" to "hypotenuse"

Sin is the ratio of "opposite" to "hypotenuse"

We will write the trig ratios with respect to the angle "x"

Opposite Side is "c"

Adjacent Side is "b"

Hypotenuse is the side opposite of 90 degree angle, "a"

Now, let's write the ratios:

Sin \ x =\frac{c}{a}\\Cos \ x = \frac{b}{a}\\Tan \ x = \frac{c}{b}

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8 0
3 years ago
What is the area of this? Please help
Slav-nsk [51]

Answer:

<u>364 cm²</u>

Step-by-step explanation:

Area of the figure :

  • Area (triangle) + Area (rectangle 1) + Area (rectangle 2) + Area (rectangle 3)
  • 1/2 x 20 x 14 + 12 x 9 + 7 x 3 + 19 x 5
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3 0
2 years ago
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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
Find the shorter base of a trapezoid if the trapezoid's area is 52, its altitude is 8, and its longer basis 10.
DiKsa [7]

Answer:

The shorter base is 3

Step-by-step explanation:

a =  \frac{(b1 + b2)}{2}  \times h

52 =  \frac{(10 + b2)}{2}  \times 8

b2 = 3

8 0
3 years ago
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