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3 years ago

What is 2x-5/3=7? Plz help!

1 answer:

5 0

Hello! And thank you for your question!

First add 5/3 to both sides:

2x = 7 + 5/3

Then simplify 7 + 5/3:

2x = 26/3

Then divide both sides by 2:

x = 26/3 over 2

After that simplify 26/3/2:

x = 26 over 3 x 2

Simplify 3 x 2:

x = 26/6

Simplify:

x = 13/3 or 4 1/3

Final Answer:

x = 13/3 or 4 1/3

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Somebody please help me. I cant figure this out once so ever.

WITCHER [35]

Answer:

Step-by-step explanation:

The Fibonacci sequence is the sum of the two terms before it. It looks like this:

1, 1, 2, 3, 5, 8, 13, 21, 34, ...

As you can see, 13 and 21 are indeed consecutive terms.

7 0

3 years ago

I WILL GIVE BRAINLIEST!

Illusion [34]

Answer:

24 ft cubed

Step-by-step explanation:

The volume of a rectangular prism is denoted by the formula: $V=lwh$ , where $l$ is the length, w is the width, and h is the height.

Looking at the diagram, we can see that the length is 2 ft (so $l$ = 2), the width is 4 ft (so w = 4), and the height is 3 ft (so h = 3). Now, we can just plug in these values to find V, the volume:

$V=lwh$

$V=2*4*3=24$

Thus, the answer is 24 ft cubed.

Hope this helps!

7 0

3 years ago

Read 2 more answers

What is the value of m in this equation -4(m+6)=-8

Darina [25.2K]

-4m-24=-8
(add 24 to both sides)
-4m=16
(divide by -4 on both sides)
m=-4

8 0

3 years ago

Read 2 more answers

Can you show examples of collinearpoints

Dominik [7]

Three or more points that lie on the same line are collinear points. for example let’s say points D , B and E like on line N. does this help?

6 0

2 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

1 year ago