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Gelneren [198K]

3 years ago

7

A jeweler needs to melt some 18 -karat gold to make a necklace. The melting point for 18-karat gold is 1700 Fahrenheit. Convert

this Fahrenheit temperature to a Celsius temperature. Round your answer to one decimal place.

1 answer:

nordsb [41]3 years ago

4 0

Answer: 926.7°C

Step-by-step explanation:

1700°F=926.7°C

(1700°F-32)•5/9=926.667°C

926.667°C rounded to one decimal place 926.7°C

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Amelia randomly selects two cards, with replacement, from a normal deck of cards. Calculate the probability that: the first card

Lena [83]

Answer:

1 / 2704

Step-by-step explanation:

Number of cards in a deck = 52

9 of clubs in a deck = 1

10 of clubs in a deck = 1

Probability = required outcome / Total possible outcomes

P(9 of club) = 1 / 52

With replacement ;

Then ;

P(10 of club) = 1 / 52

Hence,

P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704

3 0

2 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

2 years ago

The set of blue lines in the graph below are parallel lines. If the lines are translated, 4 units to the right and 3 units down,

EastWind [94]

Answer:

A(0,-3) B (5,0) C(0,-7)D(5,-4)

Step-by-step explanation:

8 0

2 years ago

What is the slope??????

OleMash [197]

Slope is how much a line goes up in ratio to how much the line goes to the right
(rise) / (run)
(y2 - y1) / (x2 - x1) when given points (x1, y1) and (x2, y2)
every time you go to the Right 1 unit, how much it goes Up is the slope
(if it is down, the slope is negative)

7 0

3 years ago

Please help with math

Crank

Answer:

i think it is y=2x

Step-by-step explanation:

8 0

2 years ago