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asambeis [7]
3 years ago
7

Which values from the given replacement set make up the solution set of the inequality? 2b–4≥2 ; {1,2,3,4} {1,2} {3,4} {1,2,3} {

2,3,4}
Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
Simply sub in the points from each set and solve to see if they are greater than or equal to 2
2*1-4=-2 NO
2*2-4=0 NO
2*3-4=2 YES

Therefore, any numbers 3 or above make up the solution; the answer is {3, 4}

Hope this helps!
mote1985 [20]3 years ago
8 0

Answer: {3,4} good luck!! :^)

Which values from the given replacement set make up the solution set of the inequality?

2b–4≥2 ; {1,2,3,4}  

{1,2} No.

{3,4} Yes!

{1,2,3} No.

{2,3,4} No.

Your answer should be 3,4 hope it helps and good luck!

You might be interested in
The difference of the squares of two positive consecutive even integers is 44 find the integers use the fact that if X represent
TiliK225 [7]

Answer:

The 2 integers are 10 and 12

Step-by-step explanation:

Translate it into english

"The difference (some subtraction) of the squares of two positive consecutive integers (x^2 and (x+2)^2) is (=) 44 (44)"

this means the following:

(x+2)^2-x^2=44

solve for x to find the smaller integer

first, expand

(x^2+4x+4)-x^2=44

x^2+4x+4-x^2=44

4x+4=44

4x=40

x=10\rightarrow x+2=10+2=12

The 2 integers are 10 and 12

3 0
3 years ago
What do i do to find the value of an expression
Veseljchak [2.6K]

Answer:

A variable is a letter, for example x, y or z, that represents an unspecified number.

6+x=12

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12.

If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

Step-by-step explanation:

6z+4x=?

 

Solution: Replace x with 3 and z with 2 to evaluate the expression.

6z+4x=?

6⋅2+4⋅3=?

12+12=24

Hope this helps @(^_^)@

7 0
3 years ago
Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

3 0
3 years ago
Find the critical value of t for a sample size of 23 and a 99% confidence level. choose the correct value from below:
Kay [80]
We can find critical value by using t - table.
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.

After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.

So alpha for two tailed test is 100 - 0.99 = 0.01

Alpha for one tailed test is 0.01/2 = 0.005.

So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
 SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.

8 0
3 years ago
The whole number 140 is divisible by 2, 3, 4, 5, 7, and 10.<br><br><br> True or False
Mariulka [41]
False. It is not divisible by 3.
4 0
3 years ago
Read 2 more answers
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